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Questions in physics

[Jawaban] Sound intensity model: [tex]L=10 \log \left(\frac{I}{I_0}\right)[/tex] [tex]L =[/tex] loudness, in decibels [tex]( dB ) ; I =[/tex] sound intensity, in watts [tex]/ m ^2 ; I_0=10^{-12}[/tex] watts [tex]/ m ^2[/tex] The loudness of a jack hammer is 96 dB. Its sound intensity is about ____ The loudness of a compactor is 94 dB. Its sound intensity is about ____ The sound intensity of the jack hammer is about ____ times the sound intensity of the compactor. The loudness of a pile driver is 112 dB. About how many times the sound intensity of the jackhammer is the sound intensity of a pile driver? Round to the nearest ten. ____

[Jawaban] A 10-ohm resistor and a 15-ohm resistor are connected in parallel. What is the total resistance of these two resistors? Select one: a. $2 \Omega$ b. $4 \Omega$ c. $6 \Omega$ d. $8 \Omega

[Jawaban] Select the correct answer. Venus is an average distance of 108.2 million kilometers from the Sun. Use the conversion factor [tex]$1 AU =1.5 \times 10^8 km$[/tex] to convert this distance from kilometers to astronomical units. Choose the closest answer. A. [tex]$0.72 AU$[/tex] B. 1.25 AU C. 3.56 AU D. 45.63 AU E. 96.12 AU

[Jawaban] What label should Patty place in the marked cell? A. Battery B. Switch C. Resistor D. Bulb

[Jawaban] An electric device delivers a current of [tex]$15.0 A$[/tex] for 30 seconds. How many electrons flow through it?

[Jawaban] Which accurately completes the statement? Conduction involves the transfer of electric charge or A. thermal energy B. light waves C. protons D. neutrons due to the movement of particles.

[Jawaban] $\beta+$ decay of ${ }^{22} Na$

[Jawaban] Which equation could be rearranged to calculate the frequency of a wave? A. wavelength = frequency/speed B. frequency = wavelength/speed C. wavelength = speed/frequency D. frequency = speed $\times$ wavelength

[Jawaban] The final velocity of an object moving in one dimension is given by the formula [tex]$v=u+a t$[/tex], where [tex]$u$[/tex] is the initial velocity, [tex]$a$[/tex] is the acceleration, and [tex]$t$[/tex] is the time. Solve this equation for [tex]$t$[/tex]. To solve for [tex]$t$[/tex], first subtract [tex]$u$[/tex] from both sides of the equation. Subtracting [tex]$u$[/tex] from both sides of the equation results in: [tex]$v-u=a t$[/tex] Solve this equation for [tex]$t$[/tex]. A. [tex]$t=(v-u)-a$[/tex] B. [tex]$t=(v-u)+a$[/tex] C. [tex]$t=a(v-u)$[/tex] D. [tex]$t=(v-u) / a$[/tex]

[Jawaban] An electric device delivers a current of [tex]$15.0 A$[/tex] for 30 seconds. How many electrons flow through it?