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Questions in physics

[Jawaban] Determine the mass of the pennies and use your labkit ruler to determine their volume. Use those values to calculate density. | Object: | Mass (g) | Diameter (cm) | Radius (½ diameter) | Height (cm) | Volume (cm³) | Density (g/cm³) | |---|---|---|---|---|---|---| | 5 pennies | 12.48 | 1.90 | 0.95 | 0.5 | 38 cm³ | 32 g/cm³ | (Volume of this stack of pennies is the volume of a cylinder, V = h × π × radius²)

[Jawaban] Test the hardness of the following objects by scratching two objects at a time. Refer to step 1 to easily identify which object is harder than the other. (a) Object A - pencil (b) Object B - sandpaper (c) Object C - iron nail (d) Object D - copper penny (e) Object E - glass (f) Object F - knife

[Jawaban] What happens when heat flows out of a liquid? A. The liquid's temperature decreases but it always remains a liquid. B. The liquid's temperature increases and its state may change from liquid to gas. C. The liquid's temperature increases but it always remains a liquid. D. The liquid's temperature decreases and its state may change from liquid to solid.

[Jawaban] Describe how electromagnetic waves are formed and travel through space.

[Jawaban] A skier with a potential energy of [tex]$137,200 J$[/tex] waits on top of a ski jump that is 200 m high. What is the mass of the skier? A. 20 kg B. 70 kg C. 137 kg D. 686 kg

[Jawaban] 1. When an object is thrown vertically upward, the value of gravitational acceleration is: A. -10 ms⁻² B. -20 ms⁻² C. +10 ms⁻² D. +20 ms⁻² 2. Which of the following is correct? A. 2gs = v_f² + v_i² B. 2S = v_f² - v_i² C. 2gs = v_f² - v_i² D. None of these 3. Motion is always considered along a: A. Curved line B. Opposite line C. Straight line D. Same line

[Jawaban] A bar magnet of magnetic moment M is bent in 'L' shape such that all the parts are of equal lengths. Then the new magnetic moment is: (1) \(\frac{M}{3}\) (2) 2M (3) \(\sqrt{3}M\) (4) \(3\sqrt{3}M\)

[Jawaban] Evaluate the expression: \( \frac{1.5 \times 10^{11} \text{ m}}{3 \times 10^{8} \text{ m/s}} = 500 \text{ s} \)

[Jawaban] The gravitational force formula is [tex]F=\frac{G m_1 m_2}{r^2}[/tex], where [tex]F[/tex] is the force between two objects, [tex]G[/tex] is the constant of gravitation, [tex]m_1[/tex] is the mass of the first object, [tex]m_2[/tex] is the mass of the second object, and [tex]r[/tex] is the distance between the objects. By rewriting the formula as [tex]r=\sqrt{\frac{G m_1 m_2}{F}}[/tex], you can find the distance between objects. Which of the following gives the distance, [tex]r[/tex], in simplest form? A. [tex]r=\frac{\sqrt{G m_1 m_2}}{F}[/tex] B. [tex]r=\frac{\sqrt{G m_1 m_2 F}}{F}[/tex] C. [tex]r=\sqrt{G m_1 m_2 F}[/tex]

[Jawaban] The resistance of a platinum wire at 0°C is 2Ω and 6Ω at 80°C. The temperature coefficient of resistance of the wire is: (1) 3×10⁻³ °C⁻¹ (2) 0.25 × 10⁻¹ °C⁻¹ (3) 0.25 × 10⁻² °C⁻¹ (4) 0.25 °C⁻¹