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[Jawaban] Johan found that the equation $-2|8-x|-6=-12$ had two possible solutions: $x=5$. Is he correct and why? A. He is correct because both solutions satisfy the equation. B. He is not correct because he made a sign error. C. He is not correct because there are no solutions. D. He is not correct because there is only one solution: $x=5$.
[Jawaban] Find the eighth term of the geometric sequence, given the first term and common ratio. [tex] \begin{array}{c} a_1=6 \text { and } r=-\frac{1}{3} \\ a_8=-\underline{[?]} \end{array} [/tex]
[Jawaban] Step 5 The final line in the table will reflect the total amount owed from April 28 to the date of the bill, May 14. Thus, there will be 16 days of the [tex]$540.37$[/tex] balance from April 28. \begin{tabular}{|l|l|l|l|l|} \hline Date & Payment or Purchases (in \$) & Balance Each Day (in \$) & Days & Unpaid Balance * No. of Days (in \$) \hline Apr 14 & & 656 & & \hline AB/ 17 & 151.56 & [tex]$656+151.56=807.56$[/tex] & 5 & [tex]$5 \cdot 656+151.56=3,431.56$[/tex] \hline Apr 21 & 26.45 & [tex]$807.56+26.45=834.01$[/tex] & 2 & [tex]$2 \cdot 807.56+26.45=1,641.57$[/tex] \hline *** 25 & -500 & [tex]$834.01-500=334.01$[/tex] & 4 & [tex]$4 \cdot 834.01-500=2,836.04$[/tex] \hline Apr 28 & 206.36 & [tex]$334.01+206.36=540.37$[/tex] & 3 & [tex]$3 \cdot 334.01+206.36=1,208.39$[/tex] \hline & & & 16 & [tex]$16 \cdot 540.37=8645.92 \sim 8,845.92$[/tex] \hline \end{tabular} What is the sum of the number of days in the billing cycle? (Hint: this is the sum of the "Days" column.) [tex]$70\ \textgreater \ 30$[/tex] day What is the sum of the total amounts owed (in dollars) for each day of the month? (Find this is the sum of the final column.) [tex]$51776348 \sim 17,763.48$[/tex] Step 8 Age - - colate the average datic bolance. \begin{aligned} \text { Average daily balance } & =\frac{\text { Sum of the total amounts owed for each day of the month }}{\text { Number of days in the biling cycle }}\\ & =\frac{ s 17, 763, 48 }{ 30 } \end{aligned} Divide to calculate the average daily balance in dollars. (Round your result to the nearest cent.) 5592.12 592.12
[Jawaban] Divide. [tex]\frac{x^2-9}{x^2-3 x-4}-\frac{x^2+2 x-15}{x^2-x-12}[/tex] A. [tex]\frac{x+3}{x+5}[/tex] B. [tex]\frac{(x+3)(x-4)}{(x+1)(x+5)}[/tex] C. [tex]\frac{(x+3)(x+5)}{x+1}[/tex] D. [tex]\frac{(x+3)(x+3)}{(x+1)(x+5)}[/tex]
[Jawaban] $\frac{20^k}{20^4}=20^9$ $k=$
[Jawaban] Multiply the polynomials. [tex](x-5)(x^2+4x-2)[/tex] A. [tex]x^3-x^2-22x+10[/tex] B. [tex]x^3+4x^2-20x+10[/tex] C. [tex]x^3-x^2-20x+10[/tex] D. [tex]x^3+4x^2-2x+10[/tex]
[Jawaban] Solve for x. 3x = 6x - 2
[Jawaban] Write in simplified radical form with at most one radical. $\frac{\sqrt{b c}}{\sqrt[3]{b c}}$ Assume that the variables represent positive real numbers.
[Jawaban] Find the quotient of 105 divided by 15.
[Jawaban] Select the correct answer. Given the following formula, solve for $y$. $w=\frac{x-y}{2}-z$ A. $\quad y=2(w+z)-x$ B. $y=x-(2 w+z)$ C. $y=x-2(w+z)$ D. $y=2 w+z-x$
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