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Questions in Grade College

[Jawaban] Which theory aims to explore domination in all forms, including the domination of women and the environment?

[Jawaban] Select the best answer for the question. What term describes the average weather conditions in a geographic area? A. Temperature B. Weather C. Climate D. Precipitation

[Jawaban] Solve the inequality. [tex]2(4 x-3) \geq-3(3 x)+5 x[/tex]

[Jawaban] Arc CD is $\frac{1}{4}$ of the circumference of a circle. What is the radian measure of the central angle? A. $\frac{\pi}{4}$ radians B. $\frac{\pi}{2}$ radians C. $2 \pi$ radians D. $4 \pi$ radians

[Jawaban] Simplify: [tex]$\left(7 y^2+3 x y-9\right)-\left(2 y^2+3 x y-5\right)$[/tex]

[Jawaban] At its option, a financial institution may collect and maintain data on consumer loans and provide it for CRA performance evaluation purposes. A. True B. False

[Jawaban] Factor completely. [tex]$b^2-12 b+36$[/tex]

[Jawaban] 1. [tex]\frac{1}{6} \times \frac{5}{9}=[/tex] 2. [tex]\frac{2}{5} \times \frac{7}{8}=[/tex] 3. [tex]\frac{6}{7} \times \frac{2}{9}=[/tex] 4. [tex]18 \times \frac{5}{6}=[/tex] 5. [tex]\frac{5}{24} \times \frac{8}{15}=[/tex] 6. [tex]\frac{16}{7} \times \frac{21}{8}=[/tex] 7. [tex]2 \frac{11}{12} \times \frac{2}{5}=[/tex] 8. [tex]1 \frac{3}{4} \times \frac{20}{21}=[/tex] 9. [tex]4 \frac{9}{10} \times 1 \frac{1}{7}=[/tex] 10. [tex]8 \frac{1}{3} \times 4 \frac{1}{2}[/tex]

[Jawaban] Select the correct answer. Daniel's doctor diagnoses him with testicular cancer in both testes. What procedure would Daniel have to undergo to remove the cancer? A. sterilization B. circumcision C. orchidectomy D. bilateral orchidectomy E. orchidpexy

[Jawaban] Lorne subtracted $6 x^3-2 x+3$ from $-3 x^3+5 x^2+4 x-7$. Use the drop-down menus to identify the steps Lorne used to find the difference. 1. $\left(-3 x^3+5 x^2+4 x-7\right)+\left(-6 x^3+2 x-3\right)$ 2. $\left(-3 x^3\right)+5 x^2+4 x+(-7)+\left(-6 x^3\right)+2 x+(-3)$ 3. $\left[\left(-3 x^3\right)+\left(-6 x^3\right)\right]+[4 x+2 x]+[(-7)+(-3)]+\left[5 x^2\right]$ 4. $-9 x^3+6 x+(-10)+5 x^2$ 5. $-9 x^3+5 x^2+6 x-10