What is the equation of the quadratic function with a vertex at $(2,-25)$ and an $x$-intercept at $(7,0)$?

A. $f(x)=(x+3)(x-7)$
B. $f(x)=(x-3)(x+7)$
C. $f(x)=(x+2)(x+7)$
D. $f(x)=(x-2)(x-7)$

Question

What is the equation of the quadratic function with a vertex at $(2,-25)$ and an $x$-intercept at $(7,0)$?

A. $f(x)=(x+3)(x-7)$
B. $f(x)=(x-3)(x+7)$
C. $f(x)=(x+2)(x+7)$
D. $f(x)=(x-2)(x-7)$

Anonymous · Answer

The quadratic function with a vertex at (2, -25) and an x-intercept at (7, 0) can be expressed in factored form as f(x) = (x + 3)(x - 7). Hence, the answer is option A. 
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jimrgrant1 · Answer

A ;

What is the equation of the quadratic function with a vertex at $(2,-25)$ and an $x$-intercept at $(7,0)$? A. $f(x)=(x+3)(x-7)$ B. $f(x)=(x-3)(x+7)$ C. $f(x)=(x+2)(x+7)$ D. $f(x)=(x-2)(x-7)$

Answer (2)

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What is the equation of the quadratic function with a vertex at $(2,-25)$ and an $x$-intercept at $(7,0)$?

A. $f(x)=(x+3)(x-7)$
B. $f(x)=(x-3)(x+7)$
C. $f(x)=(x+2)(x+7)$
D. $f(x)=(x-2)(x-7)$