An electric device delivers a current of [tex]$15.0 A$[/tex] for 30 seconds. How many electrons flow through it?
Answer (2)
Calculate the population density for each pond by dividing the number of geese by the area of the pond.
Pond A: 1.1 88 = 80 geese per acre, Pond B: 1.3 175 ≈ 134.62 geese per acre, Pond C: 1.5 192 = 128 geese per acre, Pond D: 2.0 204 = 102 geese per acre.
Compare the population densities of the four ponds.
Pond B has the greatest population density: P o n d B .
Explanation
Understanding the Problem We are given a table with the population of geese and the area of four ponds. We need to find which pond has the greatest population density of resident geese. Population density is calculated by dividing the number of geese by the area of the pond.
Calculating Population Densities First, we calculate the population density for each pond:
Pond A: Population density = 1.1 88 = 80 geese per acre
Pond B: Population density = 1.3 175 ≈ 134.62 geese per acre
Pond C: Population density = 1.5 192 = 128 geese per acre
Pond D: Population density = 2.0 204 = 102 geese per acre
Comparing Population Densities Now, we compare the population densities of the four ponds:
Pond A: 80 geese per acre
Pond B: approximately 134.62 geese per acre
Pond C: 128 geese per acre
Pond D: 102 geese per acre
Comparing these values, we see that Pond B has the highest population density.
Final Answer Therefore, Pond B has the greatest population density of resident geese.
Examples
Understanding population density is crucial in wildlife management. For instance, if you're a park ranger monitoring different habitats, knowing the population density of a species in each area helps you allocate resources effectively. If one pond has a much higher density of geese, it might require more frequent cleaning or supplemental feeding to maintain a healthy ecosystem. This concept is also applicable in urban planning, where understanding population density helps in resource allocation and infrastructure development.
A current of 15.0 A flowing for 30 seconds results in a total charge of 450 coulombs. This charge corresponds to approximately 2.81 x 10^{21} electrons flowing through the device. The calculations involve understanding current, total charge, and the charge of a single electron.
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