Read the following description of a relationship:
In a board game, the player who makes the last move receives a 3-point bonus for ending the game.
Let [tex]$s$[/tex] represent the score before the endgame bonus and [tex]$f$[/tex] represent the final score.
Complete the table using the equation [tex]$f=s+3$[/tex].
| [tex]$S$[/tex] | [tex]$f$[/tex] |
|---|---|
| 1 |
| 2 | 5 |
| 3 | 6 |
| 4 |
Answer (2)
Substitute s = 1 into the equation f = s + 3 to find f = 1 + 3 = 4 .
Substitute s = 4 into the equation f = s + 3 to find f = 4 + 3 = 7 .
Complete the table with the calculated values.
The completed table has f = 4 when s = 1 and f = 7 when s = 4 , so the missing values are 4 , 7 .
Explanation
Understanding the Problem We are given the equation f = s + 3 , where s is the score before the endgame bonus and f is the final score. We need to complete the table using this equation.
Calculating f for s=1 For s = 1 , we substitute s = 1 into the equation f = s + 3 to find the corresponding value of f . Thus, f = 1 + 3 = 4 .
Calculating f for s=4 For s = 4 , we substitute s = 4 into the equation f = s + 3 to find the corresponding value of f . Thus, f = 4 + 3 = 7 .
Completing the Table Now we can complete the table with the calculated values of f .
Examples
Imagine you're playing a board game where every player gets an additional 3 points at the end. This problem helps you calculate each player's final score by simply adding 3 to their score before the bonus. This is a basic example of how linear equations can be used in everyday situations to adjust scores or values.
The table is completed using the equation f = s + 3 with values calculated for each corresponding s . The completed values in the table are: f = 4 for s = 1 and f = 7 for s = 4 . Therefore, the final table reflects the relationship between s and f accurately.
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