3 years ago from now, the age of the father was 14 years more than twice his son's age. After how many years from now will he be twice his son's age?

1. 11
2. 12
3. 8
4. 14

To solve this problem, we need to use some algebra.
Let's first set up what we know:

Let the current age of the son be s .
Then the current age of the father is f .

According to the problem, 3 years ago:

The father's age was "14 years more than twice his son's age". So, we can express this as: f − 3 = 2 ( s − 3 ) + 14
Simplifying the expression: f − 3 = 2 s − 6 + 14 f = 2 s + 5 ( 1 )


Next, we need to determine how many years from now the father will be twice the son's age:

Let x be the number of years from now. So, in x years, the son's age will be s + x and the father's age will be f + x .

We want the father's age to be twice the son's age: f + x = 2 ( s + x )
Simplify this equation: f + x = 2 s + 2 x f = 2 s + x ( 2 )


Now, we substitute equation ( 1 ) into equation ( 2 ) : 2 s + 5 = 2 s + x
Since the 2 s terms cancel out, we have: 5 = x
So, in 5 years from now, the father will be twice the age of his son.
Thus, the correct multiple choice answer is not listed among the provided options.

Answered by JessicaJessy | 2025-07-21

The father will be twice the age of his son in 11 years. Thus, the correct multiple choice answer is option 1.
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Answered by JessicaJessy | 2025-07-22