7. Solve the chain sums below (multi-step problems).

a) 563 + 234 - 455 =

b) 373 + 415 - 567 =

c) 166 + 723 - 454 =

8. Divide by grouping.

A. 27 ÷ 4 =

B. 19 ÷ 3 =

C. 36 ÷ 7 =

Let's solve the given problems step-by-step:
Chain Sums
a)
563 + 234 − 455

First, add 563 and 234 : 563 + 234 = 797
Next, subtract 455 from the result: 797 − 455 = 342 So, the answer is 342 .

b)
373 + 415 − 567

First, add 373 and 415 : 373 + 415 = 788
Next, subtract 567 from the result: 788 − 567 = 221 So, the answer is 221 .

c)
166 + 723 − 454

First, add 166 and 723 : 166 + 723 = 889
Next, subtract 454 from the result: 889 − 454 = 435 So, the answer is 435 .

Divide by Grouping
A.
27 ÷ 4

Divide 27 by 4 :
4 goes into 27 a total of 6 times (since 4 × 6 = 24 ).
This leaves a remainder of 3 because 27 − 24 = 3 . Therefore, 27 ÷ 4 is 6 with a remainder of 3 , or it can be written as 6 4 3 ​ .



B.
19 ÷ 3

Divide 19 by 3 :
3 goes into 19 a total of 6 times (since 3 × 6 = 18 ).
This leaves a remainder of 1 because 19 − 18 = 1 . Therefore, 19 ÷ 3 is 6 with a remainder of 1 , or it can be written as 6 3 1 ​ .



C.
36 ÷ 7

Divide 36 by 7 :
7 goes into 36 a total of 5 times (since 7 × 5 = 35 ).
This leaves a remainder of 1 because 36 − 35 = 1 . Therefore, 36 ÷ 7 is 5 with a remainder of 1 , or it can be written as 5 7 1 ​ .

Answered by MasonWilliamTurner | 2025-07-21