3. Sederhanakanlah pernyataan di bawah ini
dalam pangkat positif.
a. (3a2b-2)3 x (2a")-2
b. (5x4y6)-3x (52xy-1)3
(5m²n 3) 2 x 2(m2n³)²
c.
d. (6a5b-4)-3 x 2(a³b-3)2
e.
(x2)2 (12)-3
y
+3
X
f.
(3)-2(2x7)2
X
JA
3x5
g.
(2a4b-2)3 (22a-3b2)-1
c²
C
h.
(m²n³)2
p-3
× (mnp-2)-3
i.
(4c4d 3)2
(3c)-2
9
d
j.
6(m²n-2)-3. (6m³n)2
mn-4
m²²n
Answer (1)
Jawaban:udah lengkap iniPenjelasan dengan langkah-langkah:a. (3a²b⁻²)³ × (2aⁿ)⁻²= 3³ a⁶ b⁻⁶ × 2⁻² a⁻²ⁿ= 27 a⁶ b⁻⁶ × 1/4 × a⁻²ⁿ= (27/4) a^(6-2n) b⁻⁶= 27a^(6-2n) / (4b⁶)b. (5x⁴y⁶)⁻³ × (5²xy⁻¹)³= 5⁻³ x⁻¹² y⁻¹⁸ × 5⁶ x³ y⁻³= 5³ x^(-12+3) y^(-18-3)= 125 x⁻⁹ y⁻²¹= 125 / (x⁹y²¹)c. (5m²n³)² × 2(m²n³)²= (25 m⁴ n⁶) × (2 m⁴ n⁶)= 50 m⁸ n¹²d. (6a⁵b⁻⁴)⁻³ × 2(a³b⁻³)²= 6⁻³ a⁻¹⁵ b¹² × 2 a⁶ b⁻⁶= (1/216) a⁻¹⁵ b¹² × 2 a⁶ b⁻⁶= (2/216) a^(-15+6) b^(12-6)= (1/108) a⁻⁹ b⁶= b⁶ / (108a⁹)e. (x²)² (y²)⁻³ / x³y³= x⁴ y⁻⁶ / (x³ y³)= x^(4-3) y^(-6-3)= x y⁻⁹= x / y⁹f. (3)⁻² (2x⁷)² / 3x⁵= (1/9)(4x¹⁴) / (3x⁵)= (4x¹⁴ / 9) / (3x⁵)= 4x¹⁴ / (27x⁵)= 4x⁹ / 27g. (2a⁴b⁻²)³ (2²a⁻³b²)⁻¹= (8a¹²b⁻⁶)(1/(4a⁻³b²))= (8/4) a^(12+3) b^(-6-2)= 2a¹⁵ b⁻⁸= 2a¹⁵ / b⁸h. (m²n³)² p⁻³ × (mnp⁻²)⁻³= m⁴n⁶p⁻³ × m⁻³n⁻³p⁶= m^(4-3) n^(6-3) p^(-3+6)= m¹n³p³= mnp³n³i. (4c⁴d³)² (3c)⁻² / (9d)= (16c⁸d⁶)(1/(9c²)) / (9d)= 16c^(8-2)d⁶ / (81d)= 16c⁶d⁵ / 81j. 6(m²n⁻²)⁻³ (6m³n)² / (m n⁻⁴)= 6m⁻⁶n⁶ × 36m⁶n² / (mn⁻⁴)= 216m⁰n⁸ / (mn⁻⁴)= 216 n^(8+4) / m= 216n¹² / m
