Tolong berikan cara dan jawabannya

1) [tex] \frac{6}{2 \sqrt{3} } \times \frac{2 \sqrt{3} }{\\ 2 \sqrt{3} } \\ = \frac{12 \sqrt{3} }{2 {}^{2} \times \sqrt{3} {}^{2} } = \frac{12 \sqrt{3} }{12} \\ \\ = \sqrt{3} [/tex]2)[tex] - \frac{1}{ \sqrt{7} } \times \frac{ \sqrt{7} }{ \sqrt{7} } = - \frac{1 \times \sqrt{7} }{ \sqrt{7}^{2} } = - \frac{ \sqrt{7} }{7} [/tex]3)[tex] \frac{9}{ \sqrt{2 + \sqrt{5} } } \times \frac{ \sqrt{2 + \sqrt{5} } }{ \sqrt{2 + \sqrt{5} } } \\ = \frac{9 \times \sqrt{2 + \sqrt{5} } }{ (\sqrt{2 + \sqrt{5} } ) {}^{2} } \\ = \frac{9 \sqrt{2 + \sqrt{5} } }{2 + \sqrt{5} } [/tex]4)[tex] \frac{3}{2 \sqrt{3} + 3} \times \frac{2 \sqrt{3} - 3}{2 \sqrt{3} - 3 } \\ = \frac{3(2 \sqrt{3} - 3) }{(2 \sqrt{3} + 3)(2 \sqrt{3} - 3) } \\ = \frac{6 \sqrt{3} - 9 }{4 \times 3 - 9} \\ = \frac{6 \sqrt{3} - 9}{12 - 9} \\ = \frac{6 \sqrt{3} - 9}{3} \\ = 2 \sqrt{3} - 9[/tex]5)[tex] \frac{4 \sqrt{2} }{ \sqrt{6} - \sqrt{2} } \times \frac{ \sqrt{6} + \sqrt{2} } { \sqrt{6} + \sqrt{2} } \\ = \frac{(4 \sqrt{2} )( \sqrt{6} + \sqrt{2} ) }{( \sqrt{6} - \sqrt{2} ) ( \sqrt{6} + \sqrt{2}) } \\ = \frac{8 \sqrt{3} - 8 }{6 - 2} \\ = \frac{8 \sqrt{3} - 8 }{4} = 4 \sqrt{3} - 8[/tex]6)[tex] \frac{7}{2 \sqrt{5} + \sqrt{6} } \times \frac{2 \sqrt{5} - \sqrt{6} }{2 \sqrt{5} - \sqrt{6} } \\ = \frac{7( 2\sqrt{5} - \sqrt{6} )}{(2 \sqrt{5} + \sqrt{6}) (2 \sqrt{5} - \sqrt{6} )} \\ = \frac{14 \sqrt{5} - 42 \sqrt{6} }{4 \times 5 - 6} \\ = \frac{14 \sqrt{5} - 42 \sqrt{6} }{20 - 6} \\ = \frac{14 \sqrt{5} - 42 \sqrt{6} }{14} \\ = \sqrt{5} - 42 \sqrt{6} [/tex]7)[tex] \frac{1 - \sqrt{2} }{ \sqrt{14} - \sqrt{5} } \times \frac{ \sqrt{14} + \sqrt{5} }{ \sqrt{14 } + \sqrt{5} } \\ = \frac{ (1 - \sqrt{2} )( \sqrt{14} + \sqrt{5} ) }{14 - 5} \\ = \frac{ \sqrt{14} + \sqrt{5} - 2\sqrt{7} - \sqrt{10}}{9} [/tex]

Answered by georgegrady11 | 2025-08-17