Jika X=3,Y=4, dan z = -1/6 tentukan hasil operasi berikut a.x²y³z b.x³y²z‐³
Answer (2)
Jawaban:a. -96b. -93.312Penjelasan dengan langkah-langkah:[tex]a. \: {x}^{2} {y}^{3} z = ({3})^{2} ({4})^{3}( - \frac {1}{6} ) \\ = 9 \times 64 \times ( - \frac{1}{6} ) \\ = 576 \times ( - \frac{1}{6} ) \\ = - 96[/tex][tex]b. {x}^{3} {y}^{2} {z}^{ - 3} \: = ({3})^{3}( {4})^{2} ( { - \frac{1}{6} })^{ - 3} \\ = 27 \times 16 \times ({ - 6})^{3} \\ = 27 \times 16 \times ( - 216) \\ = 432 \times ( - 216) \\ = - 93.312[/tex]
Penjelasan dengan langkah-langkah:Diketahui :x = 3y = 4z = -1/6→ x²y³z→ (3)²(4)³(-1/6)→ 9 . 64 . (-1/6)→ -96→ x³y²z-³→ (3)³(4)²(-1/6)-³→ 27 . 16 . (-216)→ -93312Mapel : MatematikaKelas : 7Materi : Aljabar#LutfiproTeam
