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In Matematika / Sekolah Menengah Atas | 2025-08-14

sederhanajanlag bentuk akar dibawah ini
√24-√150-√54+√600

Asked by atiktrisnawati2022

Answer (2)

[tex]\sqrt{24} - \sqrt{150} - \sqrt{54} + \sqrt{600} [/tex][tex]= \sqrt{4 \times 6} - \sqrt{25 \times 6} - \sqrt{9 \times 6} + \sqrt{100 \times 6} [/tex][tex]= 2 \sqrt{6} - 5 \sqrt{6} - 3 \sqrt{6} + 10 \sqrt{6} [/tex][tex]= (2 - 5 - 3 + 10) \sqrt{6} [/tex][tex]= 4 \sqrt{6} [/tex]

Answered by MaulanaAlief | 2025-08-14

Jawab:Penjelasan dengan langkah-langkah:[tex]\begin{aligned} \sqrt{24} -\sqrt{150}-\sqrt{54} +\sqrt{600} &= \sqrt{6.2^2}-\sqrt{6.5^2}-\sqrt{6.3^2}+\sqrt{6.10^2} \\ &=2\sqrt6 -5\sqrt6 - 3\sqrt6 + 10\sqrt6 \\ &= (2-5-3+10)\sqrt6 \\ &= 4\sqrt6 \end{aligned}[/tex]

Answered by LyridsssAnonym | 2025-08-14