kerjakan tugas matriks kelas 11 sma halaman 152 bagian A

Jawaban:soal no 1. jawaban Dsoal no 2. jawaban Asoal no 3. jawaban Esoal no 4. jawaban Csoal no 5. jawaban BPenjelasan dengan langkah-langkah:1.[tex]\begin{pmatrix} 3 & -4 \\ 0 & 1 \end{pmatrix} \begin{pmatrix} 5 & 4 \\ -1 & -2 \end{pmatrix} = \begin{pmatrix} (3)(5)+(-4)(-1) & (3)(4)+(-4)(-2) \\ (0)(5)+(1)(-1) & (0)(4)+(1)(-2) \end{pmatrix}= \begin{pmatrix} 15+4 & 12+8 \\ 0-1 & 0-2 \end{pmatrix}= \begin{pmatrix} 19 & 20 \\ -1 & -2 \end{pmatrix}[/tex]2.[tex]\begin{pmatrix} -2 & 3 \\ 5 & 1 \end{pmatrix} \begin{pmatrix} 0 & -4 \\ -3 & 1 \end{pmatrix} = \begin{pmatrix} (-2)(0)+(3)(-3) & (-2)(-4)+(3)(1) \\ (5)(0)+(1)(-3) & (5)(-4)+(1)(1) \end{pmatrix}= \begin{pmatrix} 0-9 & 8+3 \\ 0-3 & -20+1 \end{pmatrix}= \begin{pmatrix} -9 & 11 \\ -3 & -19 \end{pmatrix}[/tex]3.[tex]\begin{pmatrix} -2 \\ 4 \end{pmatrix} \begin{pmatrix} -1 & 5 \end{pmatrix} = \begin{pmatrix} (-2)(-1) & (-2)(5) \\ (4)(-1) & (4)(5) \end{pmatrix}= \begin{pmatrix} 2 & -10 \\ -4 & 20 \end{pmatrix}[/tex]4.[tex]\begin{pmatrix} 2 & 4 \\ 3 & 1 \end{pmatrix} \begin{pmatrix} 4 & -1 \\ 2 & 5 \end{pmatrix} = \begin{pmatrix} (2)(4)+(4)(2) & (2)(-1)+(4)(5) \\ (3)(4)+(1)(2) & (3)(-1)+(1)(5) \end{pmatrix}= \begin{pmatrix} 8+8 & -2+20 \\ 12+2 & -3+5 \end{pmatrix}= \begin{pmatrix} 16 & 18 \\ 14 & 2 \end{pmatrix}[/tex]5.[tex]\begin{pmatrix} 4 & -1 \\ 5 & 3 \end{pmatrix} \begin{pmatrix} -3 & 4 \\ 5 & -1 \end{pmatrix} = \begin{pmatrix} (4)(-3)+(-1)(5) & (4)(4)+(-1)(-1) \\ (5)(-3)+(3)(5) & (5)(4)+(3)(-1) \end{pmatrix}= \begin{pmatrix} -12-5 & 16+1 \\ -15+15 & 20-3 \end{pmatrix}= \begin{pmatrix} -17 & 17 \\ 0 & 17 \end{pmatrix}[/tex]semoga membantu

Answered by revanashraf1230 | 2025-08-14