tolong jika tau dijawab, makasih.
Answer (1)
Jawaban: 3. ⁶log 6√6:⁶log 6√6 = ⁶log (6 * 6^(1/2)) = ⁶log 6^(3/2) = (3/2) * ⁶log 6 = (3/2) * 1 = 3/2 4. ³log 1 + ³log 3 + ³log 9 + ³log 27:³log 1 + ³log 3 + ³log 9 + ³log 27 = 0 + 1 + 2 + 3 = 6 5. ²log 24 + ²log 6 + ²log 1/9:²log 24 + ²log 6 + ²log (1/9) = ²log (24 * 6 * (1/9)) = ²log (144/9) = ²log 16 = 4 6. Jika ²log 5 = a dan ²log 7 = b, maka ²log 35:²log 35 = ²log (5 * 7) = ²log 5 + ²log 7 = a + b 7. ²log 36 - ²log 72:²log 36 - ²log 72 = ²log (36/72) = ²log (1/2) = -1 8. ⁵log 25 ⋅ ⁵log 3 ⋅ ⁹log 16:⁵log 25 ⋅ ⁵log 3 ⋅ ⁹log 16 = 2 ⋅ ⁵log 3 ⋅ ⁹log 16Kita tahu bahwa ⁹log 16 = ⁹log 2⁴ = 4 ⋅ ⁹log 2. Jadi,2 ⋅ ⁵log 3 ⋅ 4 ⋅ ⁹log 2 = 8 ⋅ ⁵log 3 ⋅ ⁹log 2Kita bisa ubah basis logaritma:8 ⋅ (log 3 / log 5) ⋅ (log 2 / log 9) = 8 ⋅ (log 3 / log 5) ⋅ (log 2 / (2 log 3))= 4 ⋅ (log 2 / log 5) = 4 ⋅ ⁵log 2 9. ⁹log 3 + ³log 2:⁹log 3 + ³log 2 = ⁹log 9^(1/2) + ³log 2 = 1/2 + ³log 2Kita bisa ubah basis logaritma:1/2 + (log 2 / log 3) = 1/2 + ³log 2 10. ⁸log 4 + ⁸log 32 + ⁸log 2:⁸log 4 + ⁸log 32 + ⁸log 2 = ⁸log (4 * 32 * 2) = ⁸log 256 = ⁸log 8^(8/3) = 8/3Semoga ini membantu!
