Hallo kak bisa minta bantuannya kerjain ini semua ga, tolong pakai cara semuanya ya :)​

Jawaban: 1. Ubahlah dalam bentuk bilangan berpangkat - 2 x 2 x 2 = 2^3- 2 x 4 x 8 = 2 x 2^2 x 2^3 = 2^(1+2+3) = 2^6- 7 x 7 x 7 = 7^3- 8 x (1/4) x 16 = 2^3 x 2^(-2) x 2^4 = 2^(3-2+4) = 2^5- 3 x (1/9) x 81 = 3 x 3^(-2) x 3^4 = 3^(1-2+4) = 3^3 2. Tentukan hasil perhitungan bilangan berpangkat berikut - 2^5 x 2^(-3) = 2^(5-3) = 2^2 = 4- 3^(-4) x 3^7 = 3^(-4+7) = 3^3 = 27- 8^(-2) x 4^3 = (2^3)^(-2) x (2^2)^3 = 2^(-6) x 2^6 = 2^(-6+6) = 2^0 = 1- 125^(-2) x 5^5 = (5^3)^(-2) x 5^5 = 5^(-6) x 5^5 = 5^(-6+5) = 5^(-1) = 1/5- (1/2)^(-2) x (1/2)^(-3) = (1/2)^(-2-3) = (1/2)^(-5) = 2^5 = 32 3. Sederhanakan operasi bilangan berpangkat berikut (dalam bentuk pangkat) - 2^4 / 2^3 = 2^(4-3) = 2^1 = 2- (3^5 x 3^18) / 3^20 = 3^(5+18) / 3^20 = 3^23 / 3^20 = 3^(23-20) = 3^3- (2^7 x 4^8) / 8^6 = (2^7 x (2^2)^8) / (2^3)^6 = (2^7 x 2^16) / 2^18 = 2^(7+16) / 2^18 = 2^23 / 2^18 = 2^(23-18) = 2^5- (2^9 x 3^8) / 6^7 = (2^9 x 3^8) / (2 x 3)^7 = (2^9 x 3^8) / (2^7 x 3^7) = 2^(9-7) x 3^(8-7) = 2^2 x 3^1 = 4 x 3 = 12- (25^6 x 49^4) / 35^7 = ((5^2)^6 x (7^2)^4) / (5 x 7)^7 = (5^12 x 7^8) / (5^7 x 7^7) = 5^(12-7) x 7^(8-7) = 5^5 x 7^1 = 5^5 x 7 4. Sederhanakan bentuk berikut dengan menggunakan sifat bilangan berpangkat - (2x^3)^5 = 2^5 x (x^3)^5 = 32x^15- (a^2)^8 * (a^3)^(-2) = a^16 * a^(-6) = a^(16-6) = a^10- (3x)^7 * (9x)^(-3) = (3x)^7 * (3^2x)^(-3) = 3^7x^7 * 3^(-6)x^(-3) = 3^(7-6)x^(7-3) = 3x^4- (8a^3)^6 / (4a^2)^4 = (2^3a^3)^6 / (2^2a^2)^4 = (2^18a^18) / (2^8a^8) = 2^(18-8)a^(18-8) = 2^10a^10 = 1024a^10- ((3a^3)^2 x (3a^5)^3) / (3a^4)^2 = (3^2a^6 x 3^3a^15) / (3^2a^8) = (3^(2+3)a^(6+15)) / (3^2a^8) = (3^5a^21) / (3^2a^8) = 3^(5-2)a^(21-8) = 3^3a^13 = 27a^13 5. Sederhanakan bentuk berikut dengan menggunakan sifat bilangan berpangkat - 5^2457 x 5^(-2458) = 5^(2457-2458) = 5^(-1) = 1/5- 4^1247 x 2^7506 = (2^2)^1247 x 2^7506 = 2^2494 x 2^7506 = 2^(2494+7506) = 2^10000- 5^10000 / 5^9999 = 5^(10000-9999) = 5^1 = 5- 27^32 / 3^(-1) = (3^3)^32 / 3^(-1) = 3^96 / 3^(-1) = 3^(96-(-1)) = 3^(96+1) = 3^97- (8^24 x 4^9) / 32^20 = ((2^3)^24 x (2^2)^9) / (2^5)^20 = (2^72 x 2^18) / 2^100 = 2^(72+18) / 2^100 = 2^90 / 2^100 = 2^(90-100) = 2^(-10) = 1/2^10 = 1/1024 Semoga penjelasan ini membantu!

Answered by ara1412 | 2025-08-13