tolong sertain cara ngerjainnya yang no 3 & 5 aja dong kakkk, pleaseeee​

Soal 3: Keliling dan Luas Daerah yang DiarsirKeliling daerah yang diarsir = jumlah sisi luarSisi atas = (8x - 4) - x = 7x - 4Sisi kanan = 3x - 1Sisi bawah = 8x - 4Sisi kiri = 3x - 1Keliling = (7x - 4) + (3x - 1) + (8x - 4) + (3x - 1)Keliling = 21x - 10Luas daerah yang diarsir = luas persegi panjang besar - luas persegi kecilLuas besar = (8x - 4)(3x - 1) = 24x^2 - 8x - 12x + 4 = 24x^2 - 20x + 4Luas kecil = x * x = x^2Luas daerah diarsir = 24x^2 - 20x + 4 - x^2 = 23x^2 - 20x + 4---Soal 4: Nilai a, b, c, d, e dari Perkalian Polinomiala. A(x) = (x^2 + 4x - 3)(-x^2 - 2x + 1)A(x) = x^2(-x^2 - 2x + 1) + 4x(-x^2 - 2x + 1) - 3(-x^2 - 2x + 1)= (-x^4 - 2x^3 + x^2) + (-4x^3 - 8x^2 + 4x) + (3x^2 + 6x - 3)= -x^4 - 6x^3 - 4x^2 + 10x - 3Jadi: a = -1, b = -6, c = -4, d = 10, e = -3b. A(x) = (x^3 + 2x^2 - 5x + 1)(2x - 3)= x^3(2x - 3) + 2x^2(2x - 3) - 5x(2x - 3) + 1(2x - 3)= (2x^4 - 3x^3) + (4x^3 - 6x^2) + (-10x^2 + 15x) + (2x - 3)= 2x^4 + x^3 - 16x^2 + 17x - 3Jadi: a = 2, b = 1, c = -16, d = 17, e = -3---Soal 5: Jumlah Koefisien Suku Berpangkat Ganjil dan GenapP(x) = (4a^3 + 3a^2 - 2a - 5)(2a^2 + 3a - 3)Hitung P(1):P(1) = (41 + 31 - 21 - 5)(21 + 3*1 - 3)= (4 + 3 - 2 - 5)(2 + 3 - 3)= (0)(2) = 0Hitung P(-1):P(-1) = (4*(-1)^3 + 3*(-1)^2 - 2*(-1) - 5)(2*(-1)^2 + 3*(-1) - 3)= (-4 + 3 + 2 - 5)(2 - 3 - 3)= (-4)(-4) = 16Rumus:S_genap + S_ganjil = P(1) = 0S_genap - S_ganjil = P(-1) = 16Hitung S_ganjil:2S_ganjil = P(1) - P(-1) = 0 - 16 = -16S_ganjil = -8Hitung S_genap:2S_genap = P(1) + P(-1) = 0 + 16 = 16S_genap = 8

Answered by dorotheaday7 | 2025-08-12