Diketahui:f(x + 2) = 2x + 3g(x) = 5 - 2x^2Cari (fog)(2) = f(g(2))1. Hitung g(2):g(2) = 5 - 2*(2^2) = 5 - 2*4 = 5 - 8 = -32. Karena f(x + 2) = 2x + 3, berarti jika t = x + 2, maka f(t) = 2*(t - 2) + 3 = 2t - 4 + 3 = 2t - 13. Substitusi t = g(2) = -3 ke f(t):f(-3) = 2*(-3) - 1 = -6 - 1 = -7Jadi, (fog)(2) = -7Jawaban: a. -7