tolong jawabkan smua nya, sbelmnya terimakasih ​

1. 2^3 × 2^4 = 2^(3+4) = 2^7 = 1282. 7^0 + 4^1 = 1 + 4 = 53. (5x)^3 × x^5 = 5^3 × x^(3+5) = 125x^84. (3^4)^2 = 3^(4×2) = 3^8 = 65615. (x^3 y^-2)^2 = x^(3×2) y^(-2×2) = x^6 y^-4 = x^6 / y^46. (3^5 × 3^-2) / 3^2 = 3^(5-2) / 3^2 = 3^3 / 3^2 = 3^(3-2) = 3^1 = 37. (2^4 / 2^6)^3 = (2^(4-6))^3 = (2^-2)^3 = 2^(-6) = 1/2^6 = 1/648. (x^-1 y^2)^3 × (x^2 y^-1)^2 = x^(-3) y^6 × x^4 y^-2 = x^( -3+4 ) y^(6-2) = x y^49. ( (3 x^2 y^-1) / (x y^2) )^2 = (3 x^(2-1) y^(-1-2))^2 = (3 x y^-3)^2 = 9 x^2 y^-6 = 9 x^2 / y^610. ( (a^-1 b^3) / (a b^-1) )^-2 = (a^(-1-1) b^(3 - (-1)))^-2 = (a^-2 b^4)^-2 = a^(4) b^(-8) = a^4 / b^8

Answered by dorotheaday7 | 2025-08-12