kaka ganteng cantik imut lucu gemes gemoy gagah rupawan mohon bantuan cara pengerjaan sama jawabannya dong.. terimakasih​

Penyelesaian1. a. [tex]2^{-3} + 4^{-1}[/tex][tex]2^{-3} = \frac{1}{2^3} = \frac{1}{8}[/tex][tex]4^{-1} = \frac{1}{4}[/tex][tex]\frac{1}{8} + \frac{1}{4} = \frac{1}{8} + \frac{2}{8}[/tex][tex]= \frac{3}{8}[/tex]b. [tex]4^{-3} - 4^{-2}[/tex][tex]4^{-3} = \frac{1}{4^3} = \frac{1}{64}[/tex][tex]4^{-2} = \frac{1}{4^2} = \frac{1}{16}[/tex][tex]\frac{1}{64} - \frac{1}{16} = \frac{1}{64} - \frac{4}{64}[/tex][tex]= \frac{-3}{64}[/tex]2.[tex]a^2 = 3^2[/tex][tex]= 9[/tex][tex]\frac{a^2 \cdot b}{c} = \frac{9 \cdot 3}{4}[/tex][tex]= \frac{27}{4}[/tex]3. a. [tex](\sqrt{63})[/tex][tex]63 = 9 \times 7[/tex][tex]= 3^2 \times 7[/tex][tex]\sqrt{63} = \sqrt{3^2 \times 7}[/tex][tex]= 3\sqrt{7}[/tex]b. [tex](\sqrt{300})[/tex][tex]300 = 100 \times 3[/tex][tex]= 10^2 \times 3[/tex][tex]\sqrt{300} = \sqrt{10^2 \times 3}[/tex][tex]= 10\sqrt{3}[/tex]

Answered by vinganzbeut | 2025-08-11