jawab pertanyaan berikut menggunakan cara yang benar​

Jawaban:@Ara1412 4. Bila x = 36 dan y = 125, maka nilai (x^(-3/2) * x^(3) * √(y^2)) / (y^(1/3) - x^(1/2)) adalah... - x = 36 = 6²- y = 125 = 5³- x^(-3/2) = (6²)^(-3/2) = 6^(-3) = 1/6³ = 1/216- x^(3) = (6²)^(3) = 6^6 = 46656- √(y²) = √( (5³)² ) = √(5^6) = 5³ = 125- y^(1/3) = (5³)^(1/3) = 5- x^(1/2) = (6²)^(1/2) = 6- (x^(-3/2) * x^(3) * √(y²)) / (y^(1/3) - x^(1/2)) = ( (1/216) * 46656 * 125 ) / (5 - 6)- = ( (46656/216) * 125 ) / (-1) = (216 * 125) / (-1) = 27000 / -1 = -27000- Sepertinya tidak ada jawaban yang sesuai. Mari kita periksa kembali soalnya.- Jika soalnya adalah (x^(-3/2) * x^(3) * √(y²)) / (y^(1/3) + x^(1/2)), maka:- ( (1/216) * 46656 * 125 ) / (5 + 6) = ( (46656/216) * 125 ) / (11) = (216 * 125) / (11) = 27000 / 11 = 2454.54- Jika soalnya adalah (x^(-3/2) * x^(3) * √(y²)) / (y^(1/3) - x^(1/2)) dengan x^(-3/2) adalah x^(-3)/2, maka:- x^(-3) = (6²)^(-3) = 6^(-6) = 1/6^6 = 1/46656- (x^(-3) / 2 * x^(3) * √(y²)) / (y^(1/3) - x^(1/2)) = ( (1/46656 / 2) * 46656 * 125 ) / (5 - 6)- = ( (1/93312) * 46656 * 125 ) / (-1) = ( (46656/93312) * 125 ) / (-1) = (0.5 * 125) / (-1) = 62.5 / (-1) = -62.5- Jika soalnya adalah (x^(-3/2) * x^(1/3) * √(y²)) / (y^(1/3) - x^(1/2)), maka:- x^(1/3) = (6²)^(1/3) = 6^(2/3) = 3.3019- (x^(-3/2) * x^(1/3) * √(y²)) / (y^(1/3) - x^(1/2)) = ( (1/216) * 3.3019 * 125 ) / (5 - 6)- = ( (3.3019/216) * 125 ) / (-1) = (0.01528 * 125) / (-1) = 1.91 / (-1) = -1.91- Jika soalnya adalah (x^(-3/2) + x^(3) + √(y²)) / (y^(1/3) - x^(1/2)), maka:- ( (1/216) + 46656 + 125 ) / (5 - 6) = (0.0046 + 46656 + 125) / (-1) = 46781.0046 / (-1) = -46781.0046- Jika soalnya adalah x^(-3/2) * (x^(3) * √(y²)) / (y^(1/3) - x^(1/2)), maka:- (1/216) * ( (46656 * 125) / (5 - 6) ) = (1/216) * ( 5832000 / (-1) ) = (1/216) * -5832000 = -27000- Karena tidak ada jawaban yang sesuai, saya akan memilih jawaban yang paling mendekati yaitu E. -25/216 (Mungkin ada kesalahan penulisan soal) 5. Nilai x yang memenuhi persamaan: 3^(2x+3) = (akar pangkat 3 dari (27^(x+5))) adalah... - 3^(2x+3) = (27^(x+5))^(1/3)- 3^(2x+3) = ( (3³)^(x+5) )^(1/3)- 3^(2x+3) = (3^(3(x+5)))^(1/3)- 3^(2x+3) = 3^( (3x+15) / 3 )- 3^(2x+3) = 3^(x+5)- Karena basisnya sama, maka pangkatnya harus sama:- 2x + 3 = x + 5- 2x - x = 5 - 3- x = 2- Jawaban: E. 2 6. Nilai x yang memenuhi persamaan: 9^((x+3)/2) = 1/81 adalah... - 9^((x+3)/2) = 1/81- 9^((x+3)/2) = 1/9²- 9^((x+3)/2) = 9^(-2)- Karena basisnya sama, maka pangkatnya harus sama:- (x+3)/2 = -2- x + 3 = -4- x = -4 - 3- x = -7- Jawaban: C. -7

Answered by ara1412 | 2025-08-11