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In Matematika / Sekolah Menengah Atas | 2025-08-11

Latihan Bilangan Berpangkat 9 11). 7" × 7-6 = 73 12. (23)-2 X 2 13. 1 ½ ½) ³. ( + )² = (34)= 19. 15. 1009: 50°: 16. 1293 b заг ві -9 = : =​

Asked by pinanaa002

Answer (1)

Jawaban:11. 7ⁿ × 7⁻⁶ = 7³- 7^(n + (-6)) = 7³- n - 6 = 3- n = 3 + 6- n = 912. (2³)^-2 × 2- 2^(3 × -2) × 2 = 2^-6 × 2¹- 2^(-6 + 1) = 2^-513. (1 ½)³- (3/2)³ = 3³/2³ = 27/814. (½ + ¼)²- (2/4 + 1/4)² = (3/4)²- 3²/4² = 9/1615. 100⁹ : 50⁹- 100⁹ / 50⁹ = (100/50)⁹- 2⁹ = 51216. 12⁹ : 3⁹- 12⁹ / 3⁹ = (12/3)⁹- 4⁹ = 26214417. (3⁴)ⁿ = 1- 3^(4n) = 1- 3^(4n) = 3⁰- 4n = 0- n = 018. a²b⁻³ × a⁻⁵b⁻⁹- a^(2 + (-5)) × b^(-3 + (-9))- a^-3 × b^-12 = 1 / (a³b¹²)19. (-9)⁶ : (-9)⁴- (-9)^(6-4) = (-9)²- (-9)² = 81 Semoga membantu!

Answered by ara1412 | 2025-08-11