sederhanakan pecahan dengan penyebut berbentuk akar, akar2/akar2 + akar7[tex] \frac{ \sqrt{2} }{ \sqrt{2 + \sqrt{7} } } [/tex]
Answer (1)
Penyelesaian[tex]\frac{\sqrt{2}}{\sqrt{2} + \sqrt{7}}[/tex][tex]=\frac{\sqrt{2}}{\sqrt{2} + \sqrt{7}} \times \frac{\sqrt{2} - \sqrt{7}}{\sqrt{2} - \sqrt{7}}[/tex][tex]\sqrt{2}(\sqrt{2} - \sqrt{7}) = (\sqrt{2} \cdot \sqrt{2}) - (\sqrt{2} \cdot \sqrt{7}) = 2 - \sqrt{14}[/tex][tex](\sqrt{2} + \sqrt{7})(\sqrt{2} - \sqrt{7}) = (\sqrt{2})^2 - (\sqrt{7})^2[/tex][tex]= 2 - 7[/tex][tex]= -5[/tex][tex]= \frac{2 - \sqrt{14}}{-5}[/tex]bentuk sederhana = [tex]\frac{\sqrt{14} - 2}{5}[/tex]
