Rasionalkan bentuk diatas! tolong bantu a sampe c, pake carajangan asal, aku tunggu....makasiiii
Answer (1)
Penyelesaiana. [tex]4\sqrt{b^3} = 4b^{\frac{3}{2}}[/tex][tex]\frac{2}{4\sqrt{b^3}} \times \frac{\sqrt{b}}{\sqrt{b}} = \frac{2\sqrt{b}}{4\sqrt{b^3}\sqrt{b}}[/tex][tex]= \frac{2\sqrt{b}}{4\sqrt{b^4}}[/tex][tex]\sqrt{b^4} = b^2[/tex][tex]= \frac{2\sqrt{b}}{4b^2}[/tex][tex]= \frac{\sqrt{b}}{2b^2}[/tex]b. [tex]\frac{2}{\sqrt{3}+\sqrt{5}} \times \frac{\sqrt{3}-\sqrt{5}}{\sqrt{3}-\sqrt{5}} = \frac{2(\sqrt{3}-\sqrt{5})}{(\sqrt{3}+\sqrt{5})(\sqrt{3}-\sqrt{5})}[/tex][tex](\sqrt{3}+\sqrt{5})(\sqrt{3}-\sqrt{5}) = 3 - 5[/tex][tex]= -2[/tex][tex]= \frac{2(\sqrt{3}-\sqrt{5})}{-2}[/tex][tex]= -(\sqrt{3}-\sqrt{5})[/tex][tex]= \sqrt{5} - \sqrt{3}[/tex]c. [tex]\frac{m}{\sqrt{m}+n} \times \frac{\sqrt{m}-n}{\sqrt{m}-n} = \frac{m(\sqrt{m}-n)}{(\sqrt{m}+n)(\sqrt{m}-n)}[/tex][tex](\sqrt{m}+n)(\sqrt{m}-n) = m - n^2[/tex][tex]= \frac{m(\sqrt{m}-n)}{m-n^2}[/tex]
