Sederhanakan bilangan berpangkat berikut dan tentukan nilai p.
Answer (1)
Penyelesaian[tex]\frac{9^p}{4^3} \div \frac{26^2}{2^6} = 3^8[/tex][tex]9^p = 3^{2p}[/tex][tex]4^3 = 2^6[/tex][tex]\frac{3^{2p}}{2^6} \div \frac{26^2}{2^6} = \frac{3^{2p}}{2^6} \cdot \frac{2^6}{26^2}[/tex][tex]= \frac{3^{2p}}{26^2}[/tex][tex]\frac{3^{2p}}{26^2} = 3^8[/tex][tex]3^{2p} = 26^2 \cdot 3^8[/tex][tex]3^{2p-8} = 26^2[/tex][tex]2p - 8 = \log_{3}(26^2)[/tex][tex]= 2\log_{3} 26[/tex][tex]p = 4 + \log_{3} 26[/tex]
