In Matematika / Sekolah Menengah Pertama | 2025-08-08
Asked by annitaf72
Penyelesaian[tex]a_1 = 80[/tex][tex]r = \frac{40}{80} = \frac{1}{2}[/tex][tex]U_n = a_1 \cdot r^{n-1}[/tex][tex]U_{12} = 80 \cdot \left(\frac{1}{2}\right)^{11}[/tex][tex]= \frac{80}{2^{11}}[/tex][tex]= \frac{80}{2.048} = \frac{5}{128}[/tex]
Answered by vinganzbeut | 2025-08-08