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In Matematika / Sekolah Menengah Atas | 2025-08-07

nyatakan ke dalam bentuk bilangan bulat berpangkat a 1/6⁸ b 1/625 c(1/27)³ d 2⁵/8⁴​

Asked by ahmadsaik211

Answer (1)

SOAL A.[tex]\frac{1}{{6}^{8}} = {6}^{ - 8} [/tex]SOAL B.[tex]\frac{1}{625} = \frac{1}{{5}^{4}} = {5}^{ - 4} [/tex]SOAL C.[tex]{(\frac{1}{27})}^{3} = {(\frac{1}{{3}^{3}})}^{3} = {({3}^{ - 3})}^{3} = {3}^{ - 3 \times 3} = {3}^{ - 9} [/tex]SOAL D.[tex]\frac{{2}^{5}}{{8}^{4}} = \frac{{2}^{5}}{{({2}^{3})}^{4}} = \frac{{2}^{5}}{{2}^{3 \times 4}} = \frac{{2}^{5}}{{2}^{12}} = {2}^{5 - 12} = {2}^{ - 7} [/tex]

Answered by MaulanaAlief | 2025-08-14