HotelInfantesAgres - Tempat Tanya Jawab Pelajaran & Ilmu Pengetahuan Logo

In Matematika / Sekolah Menengah Pertama | 2025-08-06

tolong dong... terimakasih.... ​

Asked by lzzysxung

Answer (1)

Penyelesaian1. [tex]5\sqrt{2} + \sqrt{75} - 3\sqrt{32}[/tex][tex]= 5\sqrt{2} + \sqrt{25\cdot 3} - 3\sqrt{16\cdot 2}[/tex][tex]= 5\sqrt{2} + 5\sqrt{3} - 12\sqrt{2}[/tex][tex]= 5\sqrt{3} - 7\sqrt{2}[/tex]2. [tex]\frac{\sqrt{3}+\sqrt{5}}{3\sqrt{3}+2\sqrt{2}}[/tex][tex]= \frac{(\sqrt{3}+\sqrt{5})(3\sqrt{3}-2\sqrt{2})}{(3\sqrt{3}+2\sqrt{2})(3\sqrt{3}-2\sqrt{2})}[/tex][tex]= \frac{9 - 2\sqrt{6} + 3\sqrt{15} - 2\sqrt{10}}{27-8}[/tex][tex]= \frac{9 + 3\sqrt{15} - 2\sqrt{10} - 2\sqrt{6}}{19}[/tex]3. [tex]\frac{\sqrt{7}}{5-\sqrt{5}}[/tex][tex]= \frac{\sqrt{7}(5+\sqrt{5})}{(5-\sqrt{5})(5+\sqrt{5})}[/tex][tex]= \frac{5\sqrt{7}+\sqrt{35}}{25-5}[/tex][tex]= \frac{5\sqrt{7}+\sqrt{35}}{20}[/tex]

Answered by vinganzbeut | 2025-08-09