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In Matematika / Sekolah Menengah Pertama | 2025-08-05

pelis abang kakak ganteng cantik pintar butuh jawaban gwe [tex] 1.)\sqrt{20} + \sqrt{45} - 2 \sqrt{80} =... \\ 2.)2 \sqrt{27} - \sqrt{75} + \sqrt{12} =... \\ 3.)2 \sqrt{5} + \sqrt{45} =... \\ 4.)5 \sqrt{2} + \sqrt{32} - 3 \sqrt{8} = ...[/tex]​

Asked by ahsanahnafibya

Answer (1)

Penyelesaian1.[tex](\sqrt{20} + \sqrt{45} - 2\sqrt{80})[/tex][tex](\sqrt{20} = \sqrt{4 \times 5} = 2\sqrt{5})[/tex][tex](\sqrt{45} = \sqrt{9 \times 5} = 3\sqrt{5})[/tex][tex](\sqrt{80} = \sqrt{16 \times 5} = 4\sqrt{5})[/tex][tex]=\sqrt{20} + \sqrt{45} - 2\sqrt{80}[/tex][tex]= 2\sqrt{5} + 3\sqrt{5} - 2 \times 4\sqrt{5}[/tex][tex]= 2\sqrt{5} + 3\sqrt{5} - 8\sqrt{5}[/tex][tex]= (2 + 3 - 8)\sqrt{5}[/tex][tex]= (-3)\sqrt{5}[/tex]2. [tex](2\sqrt{27} - \sqrt{75} + \sqrt{12})[/tex][tex](\sqrt{27} = \sqrt{9 \times 3} = 3\sqrt{3})[/tex][tex](\sqrt{75} = \sqrt{25 \times 3} = 5\sqrt{3})[/tex][tex](\sqrt{12} = \sqrt{4 \times 3} = 2\sqrt{3})[/tex][tex]=2\sqrt{27} - \sqrt{75} + \sqrt{12}[/tex][tex]= 2 \times 3\sqrt{3} - 5\sqrt{3} + 2\sqrt{3}[/tex][tex]= 6\sqrt{3} - 5\sqrt{3} + 2\sqrt{3}[/tex][tex]= (6 - 5 + 2)\sqrt{3} = 3\sqrt{3}[/tex]3. [tex](2\sqrt{5} + \sqrt{45})[/tex][tex](\sqrt{45} = \sqrt{9 \times 5} = 3\sqrt{5})[/tex][tex]2\sqrt{5} + 3\sqrt{5} = 5\sqrt{5}[/tex]4. [tex](5\sqrt{2} + \sqrt{32} - 3\sqrt{8})[/tex][tex](\sqrt{32} = \sqrt{16 \times 2} = 4\sqrt{2})[/tex][tex](\sqrt{8} = \sqrt{4 \times 2} = 2\sqrt{2})[/tex][tex]=5\sqrt{2} + 4\sqrt{2} - 3 \times 2\sqrt{2}[/tex][tex]= 5\sqrt{2} + 4\sqrt{2} - 6\sqrt{2}[/tex][tex]= (5 + 4 - 6)\sqrt{2} = 3\sqrt{2}[/tex]

Answered by vinganzbeut | 2025-08-05