minta tolong bantu kerjakan dengan benar untuk belajar​

Penyelesaian1. [tex]\frac{7}{\sqrt{6} - \sqrt{5}} \times \frac{\sqrt{6} + \sqrt{5}}{\sqrt{6} + \sqrt{5}}[/tex][tex]= \frac{7(\sqrt{6} + \sqrt{5})}{(\sqrt{6} - \sqrt{5})(\sqrt{6} + \sqrt{5})}[/tex][tex](\sqrt{6} - \sqrt{5})(\sqrt{6} + \sqrt{5}) = (\sqrt{6})^2 - (\sqrt{5})^2[/tex][tex]= 6 - 5[/tex][tex]= 1[/tex][tex]\frac{7}{\sqrt{6} - \sqrt{5}} = 7(\sqrt{6} + \sqrt{5})[/tex]2. [tex]\frac{5 + \sqrt{5}}{\sqrt{7} - \sqrt{12}}[/tex][tex]\sqrt{12} = 2\sqrt{3}[/tex][tex]=\frac{5 + \sqrt{5}}{\sqrt{7} - 2\sqrt{3}}[/tex][tex]= \frac{5 + \sqrt{5}}{\sqrt{7} - 2\sqrt{3}} \times \frac{\sqrt{7} + 2\sqrt{3}}{\sqrt{7} + 2\sqrt{3}}[/tex][tex](\sqrt{7} - 2\sqrt{3})(\sqrt{7} + 2\sqrt{3}) = (\sqrt{7})^2 - (2\sqrt{3})^2[/tex][tex]= 7 - 4 \times 3[/tex][tex]= 7 - 12[/tex][tex]= -5[/tex][tex](5 + \sqrt{5})(\sqrt{7} + 2\sqrt{3}) = 5\sqrt{7} + 10\sqrt{3} + \sqrt{5}\sqrt{7} + 2\sqrt{5}\sqrt{3}[/tex][tex]= 5\sqrt{7} + 10\sqrt{3} + \sqrt{35} + 2\sqrt{15}[/tex][tex]= \frac{5\sqrt{7} + 10\sqrt{3} + \sqrt{35} + 2\sqrt{15}}{-5}[/tex]

Answered by vinganzbeut | 2025-08-04