hi tolong bantu di jawab ya bntar lgi di kumpulkan btw itu nmr 1 125 pangkat 2/3 × 49 pangkat 1/2. nmr 5 8 pangkat 1/3 × 16 pangkat 1/2 per 4 pangkat 1/2, yg udah jawab makasih ya

Penyelesaian1. [tex]125^{\frac{2}{3}} \times 49^{\frac{1}{2}}[/tex][tex]125^{\frac{2}{3}} = (125^{1/3})^2[/tex][tex]= (5)^2[/tex][tex]= 25[/tex][tex]49^{\frac{1}{2}} = \sqrt{49}[/tex][tex]= 7[/tex][tex]25 \times 7 = 175[/tex]2. [tex]\sqrt{8} + \sqrt{50} - \sqrt{32}[/tex][tex]\sqrt{8} = \sqrt{4 \times 2} = 2\sqrt{2}[/tex][tex]\sqrt{50} = \sqrt{25 \times 2} = 5\sqrt{2}[/tex][tex]\sqrt{32} = \sqrt{16 \times 2} = 4\sqrt{2}[/tex][tex]2\sqrt{2} + 5\sqrt{2} - 4\sqrt{2} = (2 + 5 - 4)\sqrt{2}[/tex][tex]= 3\sqrt{2}[/tex]3.  [tex](3\sqrt{2} - 4\sqrt{7})(5\sqrt{2} - 2\sqrt{7})[/tex][tex]= 3\sqrt{2} \times 5\sqrt{2} + 3\sqrt{2} \times (-2\sqrt{7})[/tex][tex]= - 4\sqrt{7} \times 5\sqrt{2} - 4\sqrt{7} \times (-2\sqrt{7})[/tex][tex]= 15(\sqrt{2}\sqrt{2}) - 6(\sqrt{2}\sqrt{7}) - 20(\sqrt{7}\sqrt{2}) + 8(\sqrt{7}\sqrt{7})[/tex][tex]= 15(2) - 6\sqrt{14} - 20\sqrt{14} + 8(7)[/tex][tex]= 30 - 6\sqrt{14} - 20\sqrt{14} + 56[/tex][tex]= (30 + 56) - (6 + 20)\sqrt{14}[/tex][tex]= 86 - 26\sqrt{14}[/tex]4. [tex]3\sqrt{729}[/tex][tex]\sqrt{729} = 27[/tex][tex]27^2 = 729[/tex][tex]3 \times 27 = 81[/tex]5. [tex]\frac{8^{\frac{1}{3}} \times 16^{\frac{1}{2}}}{4^{\frac{1}{2}}}[/tex][tex](8^{1/3} = 2) (2^3 = 8)[/tex][tex](16^{1/2} = 4 ) (4^2 = 16)[/tex][tex](4^{1/2} = 2)(2^2 = 4)[/tex][tex]2 \times 4 = 8[/tex][tex]\frac{8}{2} = 4[/tex]

Answered by vinganzbeut | 2025-08-04