In Matematika / Sekolah Menengah Pertama | 2025-08-04
Asked by kartikarahayu232
1. (3x⁻²y)³ / (9x⁻⁵y⁴)= 27x⁻⁶y³ / 9x⁻⁵y⁴= 3x⁻¹y⁻¹=3 / x¹y¹4. (2x³y⁻²) ² . (3x⁻¹y⁻³) / (x²y⁻³) ²= 2²x⁶y⁻⁴ . 3x⁻¹y⁻³ / x⁴y⁻⁶= 12x¹y⁻¹=12x¹ / y¹5. a⁻²b³ . a⁴b⁻¹= a²b²x = 2y = 27. (3a²b⁻¹)³ / (9a⁻¹b)²= 3³a⁶b⁻³ / 9²a⁻²b²= 27a⁶b⁻³ / 81a⁻²b²= 1a⁸ / 3b⁵
Answered by ssskmnr686 | 2025-08-04