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In Matematika / Sekolah Menengah Pertama | 2025-08-03

jawab no 5 gurunya galak maaf ngasih nya cuma 10 ​

Asked by fcmobile2024yyu

Answer (1)

Penyelesaian[tex](2\sqrt{3}-\sqrt{2})(3\sqrt{3}+\sqrt{2})[/tex][tex]= (2\sqrt{3}) \times (3\sqrt{3}) + (2\sqrt{3}) \times (\sqrt{2}) - (\sqrt{2}) \times (3\sqrt{3}) - (\sqrt{2}) \times (\sqrt{2})[/tex][tex](2\sqrt{3} \times 3\sqrt{3} = (2 \times 3) \times (\sqrt{3} \times \sqrt{3})[/tex][tex]= 6 \times 3[/tex][tex]= 18[/tex][tex](2\sqrt{3} \times \sqrt{2} = 2 \times \sqrt{3 \times 2}[/tex][tex]= 2\sqrt{6}[/tex][tex](-\sqrt{2} \times 3\sqrt{3} = -3(\sqrt{2} \times \sqrt{3})[/tex][tex]= -3\sqrt{6}[/tex][tex](-\sqrt{2} \times \sqrt{2} = -(\sqrt{2} \times \sqrt{2})[/tex][tex]= -2[/tex][tex]= 18 + 2\sqrt{6} - 3\sqrt{6} - 2[/tex][tex]= (18 - 2) + (2\sqrt{6} - 3\sqrt{6})[/tex][tex]= 16 - \sqrt{6}[/tex]

Answered by vinganzbeut | 2025-08-03