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In Matematika / Sekolah Menengah Pertama | 2025-07-24

Uji kompetensi!1) Tentukan nilai dari persamaan berikut!a.) 2 ^ (x + 5) = 8xb.) 125x + 7 = 253x - 4C) 64 ^ (5x - 1) = 16 ^ (3x + 3)2.) Sederhanakanlah :a.) ((8a ^ - 3 * b ^ 2 * c) ^ 2)/(4a ^ 4 * b ^ - 3 * c ^ 3) =b.) ((a ^ 3 * b ^ 2) ^ 3)/((a ^ 5 * b ^ - 4) - 2) =(4p^ -4 q^ -7 ). (2p ^ 8 * q ^ 10) =​

Asked by nadinputrimadania1

Answer (4)

Let
x--------> the number of blue beads
y--------> the number of red beads
we know that
x + y = 49
x = 49 − y -------> equation 1
x = 6 y ------> equation 2
equate equation 1 and equation 2
49 − y = 6 y 6 y + y = 49 7 y = 49 y = 7 49 ​ y = 7
find the value of x
x = 6 ∗ 7 x = 42
therefore
the answer is
Ivan has 42 b l u e b e a d s

Answered by calculista | 2024-06-11

The total number of blue beads with Ivan is 42 ​ . ;

Answered by AkhileshT | 2024-06-12

Ivan has 42 blue beads. This is found by defining the number of blue and red beads, setting up and solving equations based on the relationships given in the problem. By substituting values, we determined there are 7 red beads and subsequently 42 blue beads.
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Answered by calculista | 2024-10-09

1. Tentukan nilai x dari persamaan berikut: a.) 2x + 5 = 8x 2x - 8x = -5-6x = -5x = 5/6 b.) 125x+7 = 253x-4 Karena 125 = 5³ dan 25 = 5², persamaan dapat ditulis sebagai:(5³)x+7 = (5²)3x-453(x+7) = 52(3x-4)3(x+7) = 2(3x-4)3x + 21 = 6x - 83x = 29x = 29/3 c.) 645x-1 = 163x+3 Karena 64 = 2⁶ dan 16 = 2⁴, persamaan dapat ditulis sebagai:(2⁶)5x-1 = (2⁴)3x+326(5x-1) = 24(3x+3)6(5x-1) = 4(3x+3)30x - 6 = 12x + 1218x = 18x = 1   2. Sederhanakanlah: a.) (8a⁻³b²c)² / (4a⁴b⁻³c³) = (64a⁻⁶b⁴c²) / (4a⁴b⁻³c³)= 16a⁻¹⁰b⁷c⁻¹= 16b⁷ / (a¹⁰c) b.) (a³b²)³ / (a⁵b⁻⁴)⁻² = (a⁹b⁶) / (a⁻¹⁰b⁸)= a¹⁹b⁻²= a¹⁹ / b² c.) (4p⁻⁴q⁻⁷)(2p⁸q¹⁰)= 8p⁴q³

Answered by rzx6294 | 2025-07-24