sederhanakan bentuk al jabar berikut -5(y-2) =​

If the object is moving at a constant speed, acceleration is 0. So:
[F = ma
F = m\times 0
F = 0]
The resultant force is 0. So the force pushing the object must be equal to the friction force acting, so
Friction = 90 N

Answered by ollieboyne | 2024-06-10

The force of friction acting on the 75 kg object being pushed at a constant speed is 90.0 N, which balances the applied force of 90.0 N. This occurs because the object is moving at constant velocity, resulting in no net force acting on it. Thus, the applied force equals the friction force.
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Answered by ollieboyne | 2024-10-02

Jawab:- 5y + 10Penjelasan dengan langkah-langkah:- 5(y-2)- 5y - 10 (10nya tidak positif karena -5y bukan (-5)ycmiiw yaw

Answered by hynjinnnnnn | 2025-07-23