7^2-x-49^2-x+42 = 0tentukan nilai x​

Well you need three trucks that can pull 5 tons of sand each; that gives us 15 tons total taken care of so far, and 2 drivers left. The last two drivers drive two trucks that pull 3 tons of sand each; giving us a total of 21 tons and zero drivers left. Hope this helps!

Answered by icedraptor88 | 2024-06-10

The number of **trucks **which carry 5-tons are required 3 in number and the number of trucks which **carry **3-tons are required 2 in number.
What is an equation?
Mathematical **expressions **with two algebraic symbols on either side of the equal (=) sign are called equations.
This **relationship **is illustrated by the left and right expressions being equal to one another. The left -hand side **equals **the right -hand side is a basic, straightforward equation.
As per the information given in the question,
Let the number of 5-tons truck is x and the number of 3-tons truck is y.
Then, the **equations **as per the statement will be,
3x + 5y = 21 (i)
x + 2y = 8
x = 8 - 2y (ii)
Substitute equation (ii) in equation (i)
3(8 - 2y) + 5y = 21
24 - 6y + 5y = 21
24 - y = 21
y = 24 - 21
**y **= 3
Put y = 3 in equation (i)
3x + 5(3) = 21
3x = 21 - 15
x = 6/3
**x **= 2
To know more about equation :
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Answered by kuldeepjadhav | 2024-06-16

To move 21 tons of sand, ABLE Trucking Company needs 3 trucks that haul 5 tons each and 2 trucks that haul 3 tons each. This ensures that all 8 drivers are utilized according to the insurance requirements. The equations for weight and driver count were solved to arrive at this solution.
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Answered by kuldeepjadhav | 2024-10-15

Jawab:[tex]x=1[/tex]Penjelasan dengan langkah-langkah:[tex]7^{2-x}-49^{2-x}+42=0\\7^{2-x}-(7^2)^{2-x}+7\cdot 6=0\\7^{2-x}-7^{4-2x}+7\cdot 6=0\\7^{1-x}-7^{3-2x}+6=0\\7^{1-x}-7^{3-2x}=-6\\7^{1-x}-7^{3-2x}=1-7\\7^{1-x}-7^{3-2x}=7^0-7^1[/tex][tex]1-x=0\\x=1[/tex]dan[tex]3-2x=1\\-2x=-2\\x=1[/tex]

Answered by mastreeada | 2025-07-26