Diketahui massa molekul relatif dari (NH4) 3 X04 adalah 149 Jika Ar: N = 14 0 = 16 dan H = 1 Maka massa atom relatif x adalah​

0\ therefore\ |91|=91\\\\Other\ examples:\\\\|4|\\4 > 0\Rightarrow|4|=4\\\\|-4|\\-4 < 0\Rightarrow|-4|=-(-4)=4"> |a|= \left\{\begin{array}{ccc}a&if\ a\geq0\\-a&if\ a < 0\end{array}\right\\\\\\|91|\Rightarrow91 > 0\ therefore\ |91|=91\\\\Other\ examples:\\\\|4|\\4 > 0\Rightarrow|4|=4\\\\|-4|\\-4 < 0\Rightarrow|-4|=-(-4)=4

Answered by Anonymous | 2024-06-10

The absolute value of 91 is 91, as absolute value refers to the distance from zero on the number line and is always non-negative. Positive numbers remain unchanged under absolute value. Therefore, |91| = 91.
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Answered by Anonymous | 2024-12-26

Diketahui:Rumus senyawa: (NH₄)₃XO₄Mr (massa molekul relatif) = 149Ar: N = 14, H = 1, O = 16Langkah 1: Hitung massa bagian yang diketahui(NH₄)₃ = 3 × NH₄NH₄ = 14 (N) + 4 × 1 (H) = 14 + 4 = 18(NH₄)₃ = 3 × 18 = 54O₄ = 4 × 16 = 64Langkah 2: Jumlahkan149 = 54 (dari NH₄) + X + 64 (dari O₄)149 = 118 + XX = 149 - 118 = 31Jawaban:Massa atom relatif X adalah 31Unsur dengan massa relatif 31 adalah fosfor (P), jadi kemungkinan besar senyawa itu adalah ammonium fosfat:(NH₄)₃PO₄

Answered by SyarifAgengPrayogaM | 2025-07-23