3. Bu Mayani menjual nasi kuning di kantin sekolah dengan harga Rp5.000,00 per porsi. Bu Mayani mampu membuat 50 porsi nasi kuning dan memperoleh kerugian sebesar Rp20.000. Tentukan harga pembelian bahan pokok nasi kuning yang dijual oleh Bu Mayani!
Answer (3)
You need to form an equation: P+2/3P+1/2P=234 P+4/6P+3/6P=234 P+7/6P=234 13/6P=234 P=234/(13/6) P=108
The quantity "P" is found by creating an equation based on the given sum of "P", its two-thirds, and its half, resulting in P = 18 .
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Jawaban: Penjelasan:harga jual Rp. 5000 x 50porsi + kerugian Rp 20.000 = Rp 270000Harga bahan = Rp. 270.000 / 50 porsi = Rp. 5.400
