3 per dua di tambah enamper dua di kirang 2 per enam sqma dengan

Not sure if you are saying the acceleration is positive or negative? The equation you would use would be v=u+at, where v=final velocity u=initial velocity a=acceleration t=time. Using this if the acceleration is 2.51m/s^2: v=2.98+(2.51 1.6) v=6.996m/s If the acceleration is -2.51 m/s^2: v=2.98+(2.51 1.6) v=-1.036m/s

Answered by matthewhamill | 2024-06-10

V (ending) = at + v (initial)
V= (-2.51) (1.6) + 2.98
V= -1.036 m/s
V (using significant figures) = -1.0 m/s

Answered by bruhahafishman | 2024-06-10

The final speed of the body after 1.6 seconds of accelerating at 2.51 m/s² is approximately 7.00 m/s. Conversely, after decelerating at -2.51 m/s², its speed is approximately -1.04 m/s, indicating movement in the opposite direction.
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Answered by matthewhamill | 2024-09-05

Jawaban:4 1/6Penjelasan dengan langkah-langkah:3/2 + 6/2 - 2/6 =Samakan penyebutnya terlebih dahulu. Cari nilai KPK dari 2&6, maka didapat nilai 6= 9/6 + 18/6 - 2/6= 25/6 = 4 1/6

Answered by bagusloveganet | 2025-07-22