8. Seekor burung camar terbang setinggi 7 m di atas permukaan air laut. Seekor ikan berenang 2 m di bawah permukaan air laut. Jika burung tersebut tepat berada tegak lurus di atas ikan tersebut, maka berapakah jarak ke duanya?pliss bang jan trol bang butuh banget​

V = L e n g h t ∗ w i d h t ∗ h e i g h t V = 10 ∗ 3 ∗ 7 V = 210 in c h e s 3 ​

Answered by mariamikayla | 2024-06-10

a = 10 in b = 3 in c = 7 in V = ab c V = 10 ⋅ 3 ⋅ 7 V = 210 in 3

Answered by konrad509 | 2024-06-10

The volume of the box is calculated using the formula V = length × width × height. By substituting the dimensions (10 inches, 3 inches, and 7 inches), we find that the volume is 210 cubic inches. Therefore, the box can hold a total volume of 210 cubic inches.
;

Answered by mariamikayla | 2024-09-26

Penjelasan dengan langkah-langkah:burung tu 7 m atas permukaan lautikan tu 2 m bawah permukaan lautso total jarak di antara dorang = 7 m + 2 m = 9 meterjawapan: 9 meterplease brainliest answers

Answered by sukamatematik0 | 2025-07-20