You can get seven from substracting 16 and 9. We know that 16 = 4² and 9 = 3², so what you're looking for is 4² - 3² = 7.
I hope it will help you :-)
Let x be first number and y- second number. When you subtract first square number from second you get y 2 − x 2 and it is equal to 7. Hence y 2 − x 2 = 7 .
Find factors of right and left sides: ( y − x ) ( y + x ) = 1 ⋅ 7 .
Since y + x > y − x you have that { y + x = 7 y − x = 1 .
Add these equations: y − x + y + x = 1 + 7 , 2 y = 8 , y = 4 .
Then x=7-y=7-4=3. Answer: 4 2 − 3 2 = 7.
The two square numbers are 4 and 3, as their squares produce a difference of 7 ( 4 2 − 3 2 = 7 ).
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