Perkalian pada Perpangkatan 1. Amati dan lengkapi tabel di bawah ini: Operasi Perkalian pada Perpangkatan 63 × 62 4,22 x 4,23 74 x 74 (x64) 3 53 × 53 Operasi Perkalian 6 × 6 × 6 × 6 × 6 4.2x 4.2 x 4.2x4,2x 4.2 2x7x2x2x2x2x7x > (1/1) + ( + ) * (13) * (1) * (1) X + (=) x (3) (-~ + ) × ( − 1 ) × ( − 1 ) x ( ~-—-— ) × (+) x (- ≤ ) x ( 3 ) × (≤ ) 5x5x5 x sxs xs w/- Perpangkatan 65 4.2 B 2 Setelah melengkapi tabel di atas di dapat informasi bahwa: amxa=a Apakah aturan tersebut berlaku untuk operasi perkalian pada perpangkatan dengan basis yang berbeda? Sebagai contoh; 54 x 23. Jelaskan jawabanmu! Amati dan lengkapi tabel berikut: Pemangkatan suatu Perpangkatan Bentuk Perkalian Berulang Perpangkatan
Answer (4)
You are 3. 3 x 3 = 9. And 9 squared is 3.
The question asks to find a square number that is less than 80 and is also a multiple of 9. Let's approach this systematically.
Firstly, we should list the square numbers less than 80: 1, 4, 9, 16, 25, 36, 49, 64.
Next, we need to check which of these square numbers are multiples of 9.
Among these, only 36 is a multiple of 9 because 36 = 9 x 4.
Therefore, the number in question that is a square number and a multiple of 9, and is also less than 80, is 36.
The number you are looking for is 36, as it is both a square number (6 x 6) and a multiple of 9 that is less than 80.
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===============================PERKALIAN PADA PERPANGKATAN===============================Contoh:1. 6³ × 6² = 6⁵2. 4,2² × 4,2³ = 4,2⁵3. 7⁴ × 7⁴ = 7⁸4. x⁶ × x⁴ = x¹⁰5. 5³ × 5³ = 5⁶Aturan:Jika basis sama → pangkat dijumlah:aᵐ × aⁿ = aᵐ⁺ⁿCatatan:Jika basis berbeda (misal 5⁴ × 2³), aturan tidak berlaku.-------------------------------PEMANGKATAN DARI PERPANGKATAN-------------------------------Contoh:1. (x²) × (x²) = x⁴2. (x³)³ = x⁹3. (x⁵)² = x¹⁰4. (x³)⁴ = x¹²Aturan:(aᵐ)ⁿ = aᵐˣⁿ===============================KESIMPULAN:- aᵐ × aⁿ = aᵐ⁺ⁿ (basis sama)- (aᵐ)ⁿ = aᵐˣⁿ- Tidak berlaku jika basis berbeda===============================
