7 a = 10 − 2 h ∣ S u b t r a c t 10 7 a − 10 = − 2 h ∣ D i v i d e b y − 2 h = − 2 7 a + 5 h = − 3 2 1 a + 5 S o l u t i o n i s h = − 3 2 1 a + 5.
The **required **value of h is -(7a - 10)/2.
What are linear equation?
A** linear equation** only has one or two variables. No variables in a linear equation is raised to power greater than 1 or used as denominator of a fraction.
Now the given equation is,
7a = 10 - 2h
To solve for h let us take h on one side other terms to the other.
Therefore,
Subtracting 10 both the side
7a - 10 = 10 - 2h + 10
Solving we get,
7a - 10 = - 2h
now dividing by -2 both the side
(7a - 10)/(-2) = - 2h/(-2)
⇒ -(7a - 10)/2 = h
or, h = -(7a - 10)/2
Hence, the **required **value of h is -(7a - 10)/2.
To learn more about linear equation :
https://brainly.com/question/9093286
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To solve for h in the equation 7 a = 10 − 2 h , we rearrange and isolate h to find h = 2 10 − 7 a . This involves moving terms involving h to one side and then dividing to isolate it. Always remember to check your solution by substituting back into the original equation.
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