1.Nyatakan perkalian berulang berikut dalam perpangkatan
a.t x t x t x 2 x 2 x 2
b.1/4 x 1/4 x 1/4 x 1/4 x 1/4
c.t x y x t x y x t
2.Nyatakan perpangkatan berikut dalam bentuk perkalian berulang
a.(0,83)⁴
b.(-1/4)⁴
c.-(1/4)⁴
3.Tentukan hasil perpangkatan berikut
a.(0,02)²
b.(1/3)³
4. Nyatakan bilangan berikut dalam perpangkatan dengan basis 10
a.1.000 b.100.000 c.1.000.000 d.10.000.000
5.Nyatakan bilangan berikut dalam perpangkatan dengan basis 2
a.256 b.64 c.512 d.1.048.576
6.T

The equation given is 2m - 13 = -8m + 27. To solve for m , we need to gather all the m terms on one side and the constant terms on the other side.
Add 8m to both sides of the equation: 2m + 8m - 13 = 27, which simplifies to 10m - 13 = 27.
Add 13 to both sides of the equation: 10m = 40.
Divide both sides by 10 to find m : m = 4.
Therefore, the solution to the equation is m = 4.

Answered by qwarrow | 2024-06-18

To solve for m in the equation 2 m − 13 = − 8 m + 27 , we first combine like terms and isolate m . After simplification, we find that m = 4 .
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Answered by qwarrow | 2024-09-26

Jawaban:1. t x t x t x 2 x 2 x 2 = t³ x 2³1/4 x 1/4 x 1/4 x 1/4 x 1/4 = 1/4⁵t x y x t x y x t x y (ty)³2. 0,83⁴ = 0,83 x 0,83 x 0,83 x 0,83(-1/4)⁴ = -1/4 x -1/4 x -1/4 x -1/43. (0,02)² = 0,02 x 0,02 = 0,0004(1/3)³ = 1/3 x 1/3 x 1/3 = 1/274. 1000 = 10³100.000 = 10⁵1.000.000 = 10⁶10.000.000 = 10⁷5. 256 = 2⁸ 2x2x2x2x2x2x2x2 = 25664 = 2⁶ 2x2x2x2x2x2 = 64512 = 2⁹ 2x2x2x2x2x2x2x2x2 = 5121.048.576 = 2²⁰ 2x2x2x2x2x2x2x2x2x2x2x2x2x2x2x2x2x2x2x2 = 1.048.576semoga membantu

Answered by rizqiaaulia67 | 2025-07-18