Hitunglah hasil dari 1/2 + 2/3 adalah

That obviously depends on how much of the hour the light is turned on. Neither of them uses ANY energy when it's turned off.
The difference is (60 - 55) = 5 watts = 5 joules per second.
If the light is on for the entire hour, then the difference in energy is
(5 joule/second) x (3,600sec/hr) = 18,000 joules/hour .
Putting it in a more familiar unit . . .
(5 watts) x (1 hour) = 5 watt-hours = 0.005 Kilowatt-hour.
If your utility company charges you 25¢ per kilowatt-hour (a very high rate), then the more energy-efficient light bulb saves you (0.005) x (25¢) = 1/8 penny per hour of operation.

Answered by AL2006 | 2024-06-10

Replacing a 60-watt light bulb with a 55-watt light bulb saves 18,000 joules or 0.005 kilowatt-hours of energy per hour. This is a difference of 5 watts in power consumption. Hence, the energy saved is straightforwardly calculated from the power difference over time.
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Answered by AL2006 | 2024-12-18

Jawaban:[tex] \frac{7}{6} [/tex]Penjelasan dengan langkah-langkah:penjelasan ada di foto ya semoga membantu

Answered by mesincapit | 2025-07-18