Helen membantu Ibu menjual makanan ringan di warung. Helen memiliki 4 keping uang Rp 100, 2 keping uang Rp. 500, 5 keping uang Rp 1.000, dan 7 lembar uang Rp 2.000. Slamet membeli makanan ringan seharga Rp 7.300. Slamet membayar dengan pecahan uang Rp. 10.000. a. Uraikan uang Rp. 7.300 dengan pecahan uang yang di miliki Helen. b. Uraikan uang Rp. 10.000 dengan pecahan uang yang di miliki Helen.

Total number of students = 331 total students that travelled in car = 7 total students that travelled in bus = 331 - 7 = 324 total number of buses = 6 Now, Total number of students in each bus = total students travelling in bus / total bus = 324 / 6 = 54 students **
** So, there were 54 students in each bus.

Answered by rabinshrestha41 | 2024-06-10

331--7=324 student in 6 budes each bus will have 324/6 = 54 student in each bus.

Answered by y7gm7g | 2024-06-10

There are 54 students in each of the 6 buses used for the field trip after accounting for the 7 students who traveled by car. To find this, we first determined the number of students traveling by bus and then divided that number by the number of buses. This calculation shows that each bus carries an equal number of students.
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Answered by rabinshrestha41 | 2024-12-26

Penjelasan dengan langkah-langkah:a. uraikan rp7.300 dgn duit yg helen adakita nak cari jumlah rp7.300 dari duit yg helen ada ni:rp100 × 4 = rp400rp500 × 2 = rp1.000rp1.000 × 5 = rp5.000rp2.000 × 7 = rp14.000so helen ada cukup semua jenis duit tunak cari kombinasi yg kena dgn rp7.300, kita boleh buat:rp2.000 × 3 = rp6.000rp1.000 × 1 = rp1.000rp100 × 3 = rp300total = rp6.000 + rp1.000 + rp300 = rp7.300so jawapan utk a: 3 lembar rp2.000, 1 keping rp1.000, 3 keping rp100b. uraikan rp10.000 dgn duit yg helen adacari kombinasi yg jumlahnya rp10.000:rp2.000 × 4 = rp8.000rp1.000 × 2 = rp2.000total = rp8.000 + rp2.000 = rp10.000so jawapan utk b: 4 lembar rp2.000, 2 keping rp1.000please brainliest answers

Answered by sukamatematik0 | 2025-07-19