162/9 = 18 water bottles per case or
18:1
** The unit rate of bottles per case is given by:**
R = 18 ; To find the unit rate, we must follow the following procedure:
Divide the total number of water bottles into case numbers.
We have then:
R = 9 162
Rewriting the unit rate we have:
R = 18
The unit rate of water bottles per case is 18. This means that each case contains 18 water bottles. To find this, we divided the total number of water bottles by the number of cases.
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Jawaban:Ringkasan Pertanyaan: 1. Dua titik A dan B berjarak 3 meter, muatan +4x10⁻⁴ C dan -1x10⁻⁴ C. Titik C di antara A dan B, jarak 2 meter dari A, muatan +3x10⁻⁵ C. Hitung gaya elektrostatis pada C.2. Dua muatan masing-masing 6 x 10⁻⁶ C terpisah 3 mm. Hitung gaya interaksi. (k = 9 x 10⁹ Nm²/C²) Solusi: 1. Soal 1:- Gaya elektrostatis antara dua muatan diberikan oleh Hukum Coulomb:- F = k * |q1 * q2| / r²- di mana:- F adalah gaya elektrostatis- k adalah konstanta Coulomb (9 x 10⁹ Nm²/C²)- q1 dan q2 adalah besar muatan- r adalah jarak antara muatan- Gaya antara A dan C:- q1 = 4 x 10⁻⁴ C- q2 = 3 x 10⁻⁵ C- r = 2 m- FA_C = (9 x 10⁹ Nm²/C²) * |(4 x 10⁻⁴ C) * (3 x 10⁻⁵ C)| / (2 m)²- FA_C = (9 x 10⁹) * (12 x 10⁻⁹) / 4- FA_C = 108 / 4 = 27 N (arah: menjauhi A)- Gaya antara B dan C:- q1 = -1 x 10⁻⁴ C- q2 = 3 x 10⁻⁵ C- r = 1 m- FB_C = (9 x 10⁹ Nm²/C²) * |(-1 x 10⁻⁴ C) * (3 x 10⁻⁵ C)| / (1 m)²- FB_C = (9 x 10⁹) * (3 x 10⁻⁹) / 1- FB_C = 27 N (arah: mendekati B)- Gaya total pada C:- Karena FA_C dan FB_C searah (keduanya menuju B), maka:- F_total = FA_C + FB_C = 27 N + 27 N = 54 N- Jawaban: D. 54 N 2. Soal 2:- Gunakan Hukum Coulomb:- F = k * |q1 * q2| / r²- q1 = 6 x 10⁻⁶ C- q2 = 6 x 10⁻⁶ C- r = 3 mm = 3 x 10⁻³ m- F = (9 x 10⁹ Nm²/C²) * |(6 x 10⁻⁶ C) * (6 x 10⁻⁶ C)| / (3 x 10⁻³ m)²- F = (9 x 10⁹) * (36 x 10⁻¹²) / (9 x 10⁻⁶)- F = (324 x 10⁻³) / (9 x 10⁻⁶)- F = 36 x 10³ = 36000 N = 3,6 x 10⁴ N- Jawaban: C. 3,6 x 10⁴ N