Diketahui persamaan linear 20x - 3y = 45. Jika y adalah bilangan cacah kurang dari 10, nilai y yang mungkin adalah..
a. 2
b. 3
c. 4
d. 5
Tolong dibantu ya yang bisaaaaa... bahan buat belajar terimakasij

If the coefficient of static friction is 0.15, then 0.15 of the crate's weight shows up as a force resisting the horizontal pull. So we really only need to know the crate's weight.
Weight = (mass) x (gravity) = (25) x (9.8) = 245 newtons.
0.15 of 245 newtons = 36.75 newtons .
The force due to friction that's holding the crate back, not letting it start sliding, is 36.75 newtons. If you push it with 75 newtons of force, then that *** IS*** enough to make the crate accelerate.

Answered by AL2006 | 2024-06-10

The applied force of 75 N exceeds the maximum static friction force of approximately 36.79 N. Therefore, the crate will overcome static friction and accelerate. Thus, 75 N is sufficient to accelerate the crate.
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Answered by AL2006 | 2024-12-26

Jawaban:Soal:Diketahui persamaan linear: 20x - 3y = 45Jika y adalah bilangan cacah kurang dari 10, nilai y yang mungkin adalah...Bilangan cacah < 10 = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}Langkah-langkah:Kita uji satu per satu nilai y dari 0 sampai 9Karena bentuk persamaan: 20x = 45 + 3yMaka kita cari apakah 20x bernilai bulat (x bilangan bulat)Coba y = 0 → 20x = 45 + 0 = 45 → x = 45/20 = 2.25 ✘Coba y = 1 → 20x = 45 + 3 = 48 → x = 48/20 = 2.4 ✘Coba y = 2 → 20x = 45 + 6 = 51 → x = 51/20 = 2.55 ✘Coba y = 3 → 20x = 45 + 9 = 54 → x = 54/20 = 2.7 ✘Coba y = 4 → 20x = 45 + 12 = 57 → x = 57/20 = 2.85 ✘Coba y = 5 → 20x = 45 + 15 = 60 → x = 60/20 = 3 ✔✅ Jadi, y = 5 menghasilkan x = 3 (bilangan bulat)Jawaban: **d. 5**

Answered by pupusdwisuryoanggono | 2025-07-19