Bagaimana penjelasannya tentang nilai 8^-2 x 24^4 : 36^5 x 256^-1 adalah

This is true. All numbers that end in zero or five are divisible by 5, and a number that ends in zero is even, and all even numbers are divisible by two.

Answered by VocaMistress | 2024-06-10

Well he's correct except that what if the number is zero? Zero has no other factors (technically speaking, anyway). But aside from zero, he's completely right. Hope this helps!

Answered by icedraptor88 | 2024-06-10

Ivan is correct as numbers ending in 0 are divisible by both 2 and 5. This is because such numbers are even (divisible by 2) and are also multiples of 5. Therefore, both factors are present in any number that ends in 0.
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Answered by VocaMistress | 2025-02-09

[tex] \tt = {8}^{ - 2} \times {24}^{4} \div {36}^{5} \times {256}^{ - 1} [/tex][tex] \tt = {( {2}^{3}) }^{ - 2} \times {( {2}^{3} \times 3)}^{4} \div {( {2}^{2} \times {3}^{2}) }^{5} \times {( {2}^{8} )}^{ - 1} [/tex][tex] \tt = {2}^{ - 6} \times {2}^{12} \times {3}^{4} \div {2}^{10} \div {3}^{10} \times {2}^{ - 8} [/tex][tex] \tt = {2}^{ - 6 + 12 - 10 - 8} \times {3}^{4 - 10} [/tex][tex] \tt = {2}^{ - 12} \times {3}^{ - 6} [/tex][tex]\boxed{ \red{ \boxed{\pink{\mathcal{M \frak{ ilana} \purple{ \tt01}}}}}} [/tex]

Answered by Milana01 | 2025-07-17