16:45 di kurangi 2 jam

The answer is 0.975 L
Volume = mol/Molarity
We have molarity (0.788 M) and we need mol and volume. Let's first calculate number of moles of CaCl2 in 85.3 g:
Molar mass of CaCl2 is sum of atomic masses of Ca and Cl: Mr(CaCl2) = Ar(Ca) + 2Ar(Cl) = 40 + 2 * 35.45 = 40 + 70.9 = 110.9 g/mol
So, if 110.9 g are in 1 mol, 85.3 g will be in x mol: 110.9 g : 1 mole = 85.3 g : x x = 85.3 g * 1 mole / 110.9 x = 0.769 moles
Now, calculate the volume: V = 0.769/0.788 V = 0.975 L

Answered by JcAlmighty | 2024-06-11

The maximum volume of a 0.788 M CaCl2 solution that can be prepared using 85.3 g of CaCl2 is approximately 0.975 liters. This is calculated by first determining the moles of CaCl2 in the given mass and then applying the molarity formula to find the volume. These calculations require knowledge of molar mass and the basic relationships between mass, moles, and volume.
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Answered by JcAlmighty | 2024-10-12

Jawaban:14.45 Penjelasan dengan langkah-langkah:tinggal hitung mundur dua kali aja kaka, jam 1 adalah jam 13.00,jam 2 adalah jam 14.00 dan jam 3 adalah jam 15.00 serta jam 4 adalah 16.00, tinggal kita hitung mundur jam 16.45,yang perlu di hitung mundur hanya jam nya ya bukan menitannya jadi 16-2=14 jadi jawab nya 14.45

Answered by serliazahrotunisa | 2025-07-19